Oakland Raiders Defeat Eight Teams, with averages above 0.6
Damali Binta – Jul 17, 2012
The Oakland Raiders have consistently defeated eight teams since 1960. Looking at the bright side of a matter can be a jump start to the next dimension of accomplishments.
The Raiders have played the Tampa Bay Buccaneers seven times, and the Raiders winning average is 0.857. If you use this as a parameter, you can say that whenever the Raiders play the Buccaneers, the Raiders are likely to be victorious.
In the 26 times, the Raiders have played the Bengals, they have a winning average of 0.692. Again, the probability of the Raiders defeating the Bengals is good.
The Vikings have played the Raiders thirteen times, and the Raiders have a winning average of 0.692. The likelihood of defeating the Bengals is the same as the likelihood of defeating the Vikings, using this parameter.
The Raiders winning average with the New York Giants and the Washington Redskins is the same: it is 0.636.
Raiders have encountered the Arizona Cardinals eight times, winning five and losing three games. The average is 0.625.
Finally, the Dallas Cowboys and the Oakland Raiders have clashed on the NFL playing field ten times. The winning average favors the Raiders, with a 0.6.
In 2012, let's hope for sustained winning averages like 0.857 the Raiders have over the Tampa Buccaneers.
In general, the Raiders have a 0.5 or above winning average for 25 opponents out of the total 31 opponents they have encountered since they were founded in 1960.
Let's look at the bright side, and let's expect more victories in 2012!
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